Comments
256-192=64. 64+64=128. 128+64=192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190
Posted by jahangir1983
256-192=64. 64+64=128. 128+64=192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190
Posted by jahangir1983
256-192=64. 64+64=128. 128+64=192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190
Posted by jahangir1983
valid host range is the numbers in between, or 129-190.
Posted by crouse
Complete Question:
Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?
Answer:
256-192=64. 64+64=128. 128+64=192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190.
Posted by sagitraz
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