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subash 23-December-2007 01:41:41 PM
Comments


Below are some best website

http://www.joshgentry.com/networking/subnet.htm

http://www.networkclue.com/routing/tcpip/calculating-masks.aspx

one simple answer i could find

Given a Class B Network with subnet mask of 255.255.248.0 and a packet addressed to 130.40.32.16, Take the 2 addresses, write them in binary form, then AND them. The answer is 130.40.32.0
Posted by suresh123
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