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Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides? mariuspaul 24-September-2009 08:39:31 AMComments 256 – 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129–190. Posted by sagitraz |
Posted: 28-September-2009 02:22:55 AM By: sagitraz 256 – 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129–190. |